This perfect weave is not possible in all cases. Let's look at another example:
S=6, J=4:
0 *-----*-----*-----* 1 *-----*-----*-----* 2 *-----*-----*-----* 3 *-----*-----*-----* 4 ^ *-^---*-----*-----* 5 | ^ | *-^---*-----*-----* OUCH! ^ | ^ | |
Here we have a collision. Some lines printed in later passes overprint lines printed by earlier passes. We can see why by considering which row number is printed by a given jet number j (numbered from 0) of a given pass, p:
row(p, j) = p*J + j*S
Because J=4 and S=6 have a common factor of 2, jet 2 of pass 0 prints the same row as jet 0 of pass 3:
row(0, 2) = 0*4 + 2*6 = 12 row(3, 0) = 3*4 + 0*6 = 12
In fact, with this particular weave pattern, jets 0 and 1 of pass p+3 always overprint jets 2 and 3 of pass p. We'll represent overprinting rows by a `^' in our diagrams, and correct rows by `*':
S=6 J=4:
0 *-----*-----*-----* 1 *-----*-----*-----* 2 *-----*-----*-----* 3 ^-----^-----*-----* 4 ^-----^-----*-----* 5 ^-----^-----*-----*
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